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    Awk pattern matching

    AWK its big ... a full on programming language really

    a GooD place to get more info is in the standard *nix 'man' command


    to make a list of all the users and shell's that are in use on your box
     (not a verry practical example as there are non user enrtys in your passwd file but...)
    cat /etc/passwd | awk -F: ' {print $1 " " $7 }'
    -F: = use : as the separator ie use -F, for a csv file awk uses a space as standard
    print = print to StdOut
       $1 = the first varible found...
       " " = a space... well any string
       $7 = the 7th varible found

    This example is nice in a file ... it will serch through InPut.txt and put all lines that match into  OutPut.txt...
    awk -F, ' {
      if ( $2 ~ /^StartString/ && $2 ~ /EndString$/ ) {
        print $2
    } '  InPut.txt > OutPut.txt
     -F = as above use , as separator 
     if = well standard programing stuff really, if (this is true) { then do this}
      $2 = 2nd varible
      ~ = regexe ie patern matching (
         ^ = start of varible
         $ = end of string )
     && = logical and (for strings)
     basicly, if $2 starts with StartString and ends with EndString then print it out...

    also see: Awk

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